Find the point on graph of y=x^2 at which the tangent line is parallel to the line y=6x-1?

Here is what I have:

(f(x+h)-f(x))/h=((x+h)^2-x^2)/h=2x+h

lim (h approaching 0) 2x+h=2x y=2x (slope)

then I plugged in the slope,6 from above into y
6=2x
x=3

Then y=f(3)
3^2=9

Therefore the answer is 9?