Solving systems of Linear Equation by Graphing Method?
2014-06-24 1:35 pm
Steps for what to do? I didn't understand rise/run so how do you use it? Also, I have to do this in Slope-intercept form. This is an example - 4x = 8 + y and 4x = 3 + y. How do I solve this?
回答 (1)
2014-06-24 1:55 pm
slope-intercept form is y = mx + c. accordingly, your two equations are
y = - 4x - 8
y = 4x - 3
Two points are sufficient to draw each line.
Find these by figuring out the axis intercepts which are at x = 0 and y = 0.
y = -4x - 8: When x = 0, y = -8 and when y = 0, x = -2. The points are (0, - 8) and (-2, 0)
y = 4x - 3 gives you (0, -3) and (0.75, 0)
Draw the two lines. Their point of intersection is the solution. It should be at (-0.625, -5.5)
y = - 4x - 8
y = 4x - 3
Two points are sufficient to draw each line.
Find these by figuring out the axis intercepts which are at x = 0 and y = 0.
y = -4x - 8: When x = 0, y = -8 and when y = 0, x = -2. The points are (0, - 8) and (-2, 0)
y = 4x - 3 gives you (0, -3) and (0.75, 0)
Draw the two lines. Their point of intersection is the solution. It should be at (-0.625, -5.5)
收錄日期: 2021-04-21 00:10:56
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20140624053548AALjuil