微積分:求切線方程

cot(α-θ) = f’(θ)/f(θ) = (-sinθ)/(1+cosθ) = (-1/2)/(1+√3/2) = -(2-√3) cot(α-π/6) = -cot(5π/12) = cot(7π/12) α= 9π/12 = 3π/4 切線斜率 m = tanα= -1, 點(r,θ)=(1+√3/2,π/6) = (√3/2 + 3/4, 1/2 + √3/4) y = -(x - (√3/2 + 3/4)) + 1/2 + √3/4y = -x + √3/2 + 3/4+ 1/2 + √3/4y = -x + 3√3/4 + 5/4rsinθ= -rcosθ+ 3√3/4 + 5/4r = (3√3/4 + 5/4)/(cosθ+ sinθ)

謝謝您提醒

不曉得哪根筋不對

把r當常數去了

2014-06-21 12:06:52 補充：
參考看看

http://www.4shared.com/download/umBKR74Xce/_online.gif?lgfp=1000

Einsteine君，不對呀，dy/dθ = dr/dθ sinθ + r cosθ 才對呀！

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畾燚聶炎尛昍

2014-06-20 23:16:17 補充：
到下面的網址看看吧

▶▶http://candy5660601.pixnet.net/blog