求解S.1數學題

Cherry 同學你好~ (◕‿◕✿)

對於這類代數題，你必需好好掌握當中的做法和準繩度。

這對你將來學數學是很重要的。

If x = 2, y = 3 and z = 5, find the value of the following.

(a) 4x - 2y
= 4(2) - 2(3)
= 8 - 6
= 2

(b) (7x + 6y)(4y - 5z)
= [7(2) + 6(3)][4(3) - 5(5)]
= (14 + 18)(12 - 25)
= (32)(-13)
= -416

a)
4x-2y
=4*2-2*3
=2

b)
(7x+6y)(4y-5z)
=28xy-35xz-30yz+24y^2
=28(2)(3)-35(2)(5)-30(3)(5)+24(9)
=-416

(a) 4x - 2y
= 4(2) - 2(3)
= 8 - 6
= 2

(b) (7x + 6y)(4y - 5z)
= [7(2) + 6(3)][4(3) - 5(5)]
= (14 + 18)(12 - 25)
= (32)(-13)
= -416

If x=2,y=3 and z=5

a)4x-2y
=4x2-2x3
=8-6
=2

b)(7x2+6x3)(4x3-5x5)
=32x-13
=-416

a)4x-2y

=4*2-2*3
=8-6
=2


b)(7x+6y)(4y-5z)

=(7*2+6*3)*(4*3-5*5)
=(14+18)*(12-25)
=32*-13
=-416

4x2-2x3
=14
(7x2+6x3)x(4x3-5x5)
=(14+18)x(12-25)
=32x-13
=-416

a) 4x-2y
=(4*2)-(2*3)
=8-6
=2
the value is 2

b) (7x+6y)(4y-5z)
=(7*2+6*3)*(4*3-5*5)
=(14+18)*(12-25)
=32*-13
=-416
the value is -416

4X2-2X3=2
(7X2+6X3)(4X3-5X5)=32X2=64

I am a F.4 student :)

a:
4x - 2y
= 4(2) - 2(3)
= 8 - 6
= 2

b:
(7x + 6y) (4y - 5z)
= [7(2) + 6(3)] [4(3) - 5(5)]
= (14 + 18) (12 - 25)
= (32) (-13)
= -416