math help thanks?
Find the length of the hypotenuse of the right triangle MPQ, if tanM = square root of 6 over 5 and angle P is the right angle.
回答 (4)
tan(M) = sqrt(6) / 5 = PQ / MP
Let g = GCD(PQ, MP)
PQ = sqrt(6) * g
MP = 5 * g
MQ^2 = (sqrt(6) * g)^2 + (5 * g)^2 = 6 g^2 + 25 g^2 = 31 g^2
So MQ = sqrt(31) g
MQ = sqrt(31) * GCD(PQ, MP)
Tangent is a RATIO. You cannot assume that the legs of the triangle are √6 and 5. They are n√6 and 5n, where n is any positive number.
Since you do not know the lengths of the legs, you cannot determine the length of the hypotenuse.
first ur question is not complete..but still i will give u a answer..
tanM = sqrt6/5
means MP=5
PQ=sqrt6
hypotenuse by pyathagoras thm =MQ=sqrt(6+25)
=sqrt31
If tanM = sqrt(6)/5 then the two shorter sides of the triangle are sqrt(6) and 5
By Pythagoras Theorem
MQ ^2 = [sqrt(6)]^2 + 5^2
= 6 + 25
= 31
MQ = sqrt(31)
Hypotenuse = sqrt(31)
收錄日期: 2021-05-01 15:15:29
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