MaTh 問題

a)
lim_x→3 f(x)=3

b)
lim_x→-1 f(x)=-1

lim_x→2 [5x+3]
=5(2)+3
=13

lim_x→2 [(3x²-3x+4)/(2x²-3)]
=(3(2)²-3(2)+4)/(2(2)²-3)
=10/5
=2

2014-05-24 17:20:19 補充：
a)

lim_x→3− f(x)=3
lim_x→3+ f(x)=4.5

how about 4.5 in a)??