Maths

2014-05-22 4:09 pm
A certain number when divided by 4, remainder is 3. When divided by 7, remainder is 5. When divided by 9, remainder is 2. What is the number? Please show steps in calculation.
更新1:

To : 暴雨 Please explain how to get N = 4 x 7 x 2 + 4 x 9 x 5 + 7 x 9 + 4 x 7 x 9k. Thanks.

回答 (5)

2014-05-22 6:16 pm
✔ 最佳答案
Assume N = 4x7x2 + 4x9x5 + 7x9 + 4x7x9x(k), where k is an integer.

So, when N is divided by 4, the remainder is 3;
when divided by 7, remainder is 5;when divided by 9, the remainder is 2.

Therefore, the number N is :
56 + 180 + 63 + 252k
= 47 + 252(k + 1)

In general, this number is (47 + 252n), where n is an integer.

2014-05-22 12:26:15 補充:
As N consists 4 terms, the 1st, 2nd, 4th terms are all divisible by 4, the 3rd term, 63,
will get a remainder 3 when divided by 4.
Similarly, the 1st, 3rd, 4th terms are all divisible by 7, the 2nd term, 180,
will get a remainder 5 when divided by 7.

2014-05-22 12:28:27 補充:
And, the 2nd, 3rd, 4th terms are all divisible by 9, the 1st term, 56,
will get a remainder 2 when divided by 9.
So, N is satisfied all the requirement of the question.

2014-05-22 13:19:58 補充:
聰明,你寫出的式是課題,餘式定理的課題。
因不知問者的程度,所以只好當這只是一條問題。可能是小學生奧數問題。
2014-05-24 8:21 pm
哈!

卡通有數碼暴龍

Math有數學暴龍
2014-05-22 10:06 pm
好野呀~!

暴雨兄回歸啦~

╭∧---∧╮
│ .✪‿✪ │
╰/) ⋈ (\╯

2014-05-22 18:17:17 補充:
哈哈哈~
咁佢係咪暴龍?

數學暴龍?
2014-05-22 8:29 pm
Hi, I am a P4 student. 我有參加奧數。有些小四奧數題都有,我就是不懂 ...
2014-05-22 6:51 pm
多謝暴雨哥賜教﹗﹗﹗
雄兵哥也勁﹗﹗

2014-05-22 12:51:02 補充:
i think the pattern is
4 x 7 x __ + 7 x 9 x __ + 4 x 9 x __ + 4 x 7 x 9 x k

but the question is that what the "__" s are. you should keep trying until you get the proper remainder.

2014-05-22 15:17:29 補充:
又多一條龍喇 ^^,高手雲集,賜教﹗


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