X→0
更新1:
答案是 1/3
求下列極限值
回答 (13)
2014-05-21 12:21 pm
✔ 最佳答案
lim(x→0)[(1+x^3)^(1/3)-(1+x^5)^(1/5)]/(x^3)=lim(x→0)[(1+x^3)^(1/3)-(1+x^5)^(1/5)]'/(x^3)'.....羅畢達法則=lim(x→0){x^2*(1+x^3)^(-2/3)-x^5*(1+x^5)^(-4/5)}/3x^2=lim(x→0){(1+x^3)^(-2/3)-x^3*(1+x^5)^(-4/5)}/3={(1+0)^(-2/3)-0*(1+0)^(-4/5)}/3=1^(-2/3)/3=1/3
2014-06-21 10:43 pm
2014-06-20 9:58 pm
2014-06-05 2:15 pm
2014-06-03 3:10 pm
2014-05-30 4:19 pm
2014-05-29 4:15 pm
2014-05-28 4:07 pm
2014-05-27 12:40 pm
2014-05-24 1:36 pm
2014-05-23 12:13 pm
2014-05-22 5:03 pm
收錄日期: 2021-04-30 18:50:03
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20140519000016KK07613