三角學的應用

2014-05-18 11:04 pm
cos77°- (cos13°/tan77°)

回答 (2)

2014-05-18 11:25 pm
✔ 最佳答案
cos77°- (cos13°/tan77°)
=cos77°- [cos13°/(sin77°/cos77°)]
=cos77°- [(cos13°cos77°)/sin77°]
=cos77°- [(cos13°cos77°)/cos(90°-77°)]
=cos77°- [(cos13°cos77°)/cos13°]
=cos77°- cos77°
=0

2014-05-18 15:27:44 補充:
解釋:

tan77°=sin77°/cos77°

sin77°=cos(90°-77°)=cos13°

SO
tan77°=cos13°/cos77°
2014-05-18 11:13 pm
按小算盤就計到,有什麼難度﹖以前沒有小算盤就要查對數表。


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