✔ 最佳答案
dy/dx = y^2/x^3
dy/y^2 = dx/x^3
J dy/y^2 = J dx/x^3
- 1/y = -1/2x^2 + C
when x = 1, y = 1
so -1/1 = -1/2 + C, C = - 1/2
that is
- 1/y = - 1/2x^2 - 1/2
1/y = 1/2x^2 + 1/2
when x = 4
1/y = 1/32 + 1/2 = (1 + 16)/32 = 17/32
so y = 32/17.
2014-05-13 19:32:24 補充:
Remark : J stands for the integration sign ∫ .