Algebra Help ASAP?

1. Write an equation with the line crossing the following two points. (2,-8) (-1,-2)
.......................-2 - -8........6
.....slope m = ---------- = ----- = -2
........................-1 - 2........-3

.....equation of a line passing through points (2,-8) and (-1,-2) is
.....(y - -8) = m (x - 2) // substitute slope m = -2
.....y + 8 = -2 (x - 2)
.....y + 8 = -2x + 4
.....y = -2x - 4..............ANS


2. What are the midpoint and distance between the previous points in question 1?
.....midpoint of (2,-8) and (-1,-2) is
.....(x,y) = ((2 + -1)/2, (-8 + -2)/2)
.....(x,y) = (1/2, -5).........................ANS


3. Convert the following to vertex form and plot. 2x² +8x =-11
.....2x² +8x =-11
.....2x² +8x + 11 = 0

.....// x-coordinate of vertex is -8/4=-2
.....// y-coordinate of vertex is 2(-2)²+8(-2)+11=3
.....// vertex of parabola is at (x,y) = (-2,3)
.....// In vertex form, a = 2, h = -2 and k = 3
.....2(x+2)² + 3.................ANS


4. COMBINE 3radical12 + 6radical48
.....3√12 + 6√48 =
.....3√(2•2•3) + 6√(2•2•2•2•3) =
.....3 • 2 • √3 + 6 • 2 • 2 • √3 =
.....6√3 + 24√3 =
.....30√3..............ANS


5. simplify (long division maybe..) 2x³ + 11x² +13x +4 divided by x+4
.....2x³ + 11x² +13x +4 divided by x+4 = (x+1)(2x+1).....ANS
.....//see synthetic division below

use [ y - y_1] = { (y_2-y_1)/(x_2-x_1) } [ x - x_1 ] ; 2 point form

add the entries and divide by 2 ;..divide the distance between the original points by 2 ;

you have an equation , not a graph....use the quadratic formula...you can plot the answers on a number line ;

use synthetic division to get [ 2 x² + 3 x + 5 + ( -16 / [ x + 4 ] ) ]

other q's will take a lil time for me to work out but for the moment

4. answer is 30rad3

u must first simplify the rads. rad12 becomes rad4 (which equals 2) & rad3. rad48 becomes rad16 (which equals 4) and rad 3. now u must multiply 3 times 2 which turns to 6 rad3. and then 4 times 6 which becomes 24 rad3. now tht u have the same base rad u just add. Answer 30rad3

Good luck

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