center will be 8, =3 radius = 9
can you tell me if the information is complete?
find x intercepts of (x-4)^2+(y-3)^2=81?
2014-05-01 2:34 am
回答 (3)
2014-05-01 8:13 am
step by step solution
http://www.mathskey.com/question2answer/12464/find-x-intercepts-of-x-4-2-y-3-2-819
http://www.mathskey.com/question2answer/12464/find-x-intercepts-of-x-4-2-y-3-2-819
2014-05-01 2:49 am
The center is (4, 3) and the radius is 9.
The x intercepts occur when y = 0
(x - 4)² + (0 - 3)² = 81
x² - 8x + 16 + 9 = 81
x² - 8x - 56 = 0
x = {8 - √[-8² - 4(1)(56)]}/2 and x = {8 + √[-8² - 4(1)(56)]}/2
x = 4 - √72 and x = 4 + √72
The x intercepts occur when y = 0
(x - 4)² + (0 - 3)² = 81
x² - 8x + 16 + 9 = 81
x² - 8x - 56 = 0
x = {8 - √[-8² - 4(1)(56)]}/2 and x = {8 + √[-8² - 4(1)(56)]}/2
x = 4 - √72 and x = 4 + √72
2014-05-01 2:37 am
No, the center is (4, 3). The (x - 4) term tells you the x coordinate of the center is 4.
The (y - 3) term tells you the y coordinate of the center is 3.
The x intercepts are where y = 0, so they are the solutions to (x - 4)^2 + 3^2 = 81 or (x -4 )^2 = 81 - 9 = 72.
Complete to do what?
The (y - 3) term tells you the y coordinate of the center is 3.
The x intercepts are where y = 0, so they are the solutions to (x - 4)^2 + 3^2 = 81 or (x -4 )^2 = 81 - 9 = 72.
Complete to do what?
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