學校的練習題
1. y2 = 1/6+j8 = ( ) + j ( ) = (____)∠(____)
2. 1/5∠-90度 = ( ) + j ( ) = (____)∠(____)
3.0.1+Y2+Y3= ( ) + j ( ) = (____)∠(____)
可以請會的人寫出完整的做法嗎?
如果可以提供說明就更好了!
感激不敬 謝謝
相量複數 直角坐標 極座標
2014-04-17 5:20 pm
回答 (11)
2014-04-18 12:18 am
✔ 最佳答案
1.y2=1/6+j8=(1+48j)/6=1/6+48j/6......ans=(1/√2305+48/√2305)√2305/6;;;{1+48^2=2305}=(√2305/6)∠1.19349°=8.001736∠1.19349°.......ansNote: Q=atan(48/1)=1.19349°
2.Y3=(1/5)∠-90°=0.2[cos(-90°)+jsin(-90°)]=0.2(cos90°-jsin90°)=0.2(0-j)=-0.2j......ans
2014-04-17 16:26:25 補充：
題目錯誤修正第1題:
1.y2=1/(6+j8)
=(6-8j)/(6+8j)(6-8j)
=2(3-4j)/(36-64j^2)
=2(3-4j)/(36+64)
=2(3-4j)/100
=(3-4j)/50
=3/50-4j/50......ans
=(3/5-4j/5)/10
=0.1∠53°........ans
2014-04-17 16:27:40 補充：
Note: Q=atan(4/3)=53(deg)
2014-04-17 16:35:37 補充：
修正:
Y2=0.1∠-53°........ans
Note: Q=atan(-4/3)=-53(deg)
2014-04-17 16:38:09 補充：
3.0.1+Y2+Y3
=0.1+(3/5-4j/5)/10-0.2j
=(0.1+0.06)-(0.08+0.2)j
=0.16-0.28j.....ans
=4(4-7j)/100
=0.04*(4-7j);;;{16+49=65}
=0.04*√65*(4/√65-7j/√65)
=0.32249∠-60.2551°......ans
Note: Q=atan(-7/4)=-60.2551°
2014-05-30 4:43 pm
2014-05-29 5:28 pm
2014-05-27 1:39 pm
2014-05-24 2:35 pm
2014-05-08 2:41 pm
2014-05-02 2:02 pm
2014-05-01 3:52 pm
2014-04-29 2:50 pm
2014-04-28 2:40 pm
2014-04-17 11:56 pm
你的問題都打錯了，怎麼解呢?
( ) 不能省略
1/ (6+j8) ?
y3 = (1/5)∠-90 ?
( ) 不能省略
1/ (6+j8) ?
y3 = (1/5)∠-90 ?
收錄日期: 2021-04-30 18:46:36
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20140417000016KK02552