相量複數直角坐標極座標

2014-04-17 5:20 pm

學校的練習題

1. y2 = 1/6+j8 = ( ) + j ( ) = (____)∠(____)

2. 1/5∠-90度 = ( ) + j ( ) = (____)∠(____)

3.0.1+Y2+Y3= ( ) + j ( ) = (____)∠(____)

可以請會的人寫出完整的做法嗎?

如果可以提供說明就更好了!

感激不敬謝謝

回答 (11)

麻辣

2014-04-18 12:18 am

✔ 最佳答案

1.y2=1/6+j8=(1+48j)/6=1/6+48j/6......ans=(1/√2305+48/√2305)√2305/6;;;{1+48^2=2305}=(√2305/6)∠1.19349°=8.001736∠1.19349°.......ans
Note: Q=atan(48/1)=1.19349°
2.Y3=(1/5)∠-90°=0.2[cos(-90°)+jsin(-90°)]=0.2(cos90°-jsin90°)=0.2(0-j)=-0.2j......ans

2014-04-17 16:26:25 補充：
題目錯誤修正第1題:

1.y2=1/(6+j8)

=(6-8j)/(6+8j)(6-8j)

=2(3-4j)/(36-64j^2)

=2(3-4j)/(36+64)

=2(3-4j)/100

=(3-4j)/50

=3/50-4j/50......ans

=(3/5-4j/5)/10

=0.1∠53°........ans

2014-04-17 16:27:40 補充：
Note: Q=atan(4/3)=53(deg)

2014-04-17 16:35:37 補充：
修正:

Y2=0.1∠-53°........ans

Note: Q=atan(-4/3)=-53(deg)

2014-04-17 16:38:09 補充：
3.0.1+Y2+Y3

=0.1+(3/5-4j/5)/10-0.2j

=(0.1+0.06)-(0.08+0.2)j

=0.16-0.28j.....ans

=4(4-7j)/100

=0.04*(4-7j);;;{16+49=65}

=0.04*√65*(4/√65-7j/√65)

=0.32249∠-60.2551°......ans

Note: Q=atan(-7/4)=-60.2551°

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2014-05-30 4:43 pm

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2014-05-29 5:28 pm

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2014-05-27 1:39 pm

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