指數方程,求解

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請小心看清楚我以下沒有誤解你的發問：

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1.
3^(3x) = 27^(2x+1)
3^(3x) = (3^3)^(2x+1)
3^(3x) = 3^(3×(2x+1))
3x = 3×(2x+1)
3x = 6x+ 3
3x = -3
x = -1

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2.
4^(x+1) = 644^(x+1) = 4^3
x + 1 = 3
x = 2

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3.
2^(3x-1) = 4^x2^(3x-1) = (2^2)^x
2^(3x-1) = 2^(2 × x)
3x - 1 = 2x
x = 1

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4.
8^(3-x) = 1/648^(3-x) = 1/8²
8^(3-x) = 8^(-2)
3 - x = -2
x = 5

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5.
(1/3)^(x-1) = 27^(x-1)[3^(-1)]^(x-1) = (3^3)^(x-1)
3^(-1 × (x-1)) = 3^(3 × (x-1))
-1 × (x-1) = 3 × (x-1)
-(x - 1) = 3(x - 1)
-x + 1 = 3x - 3
4x = 4
x = 1