I would like to know how to calculate the following two questions, better to have steps stated, thanks a lot.
Q1
Amy, Brenda and 4 other friends are arranged in 2 rows of 3 in order to play a game. If May and Brenda are seated next to each other, find the number of arrangements that can be made.
I would like to why the answer is not 5! x 2! = 240?
And the correct answer is 192
Q2
A box contains 4 red balls, 6 yellow balls and 5 blue balls. Alvin repeats drawing one ball at a time randomly from the box without replacement until two balls of the same colour are drawn. Find the probability that he needs exactly three draws.
So that's mean I should consider the case as follow1st time2nd time3rd timeXYYYXXBut the answer obtained is not the correct answer of 86/195
I wish to know what's wrong with my approach and why the answer is 86/195
Thousand Thanks