✔ 最佳答案
a) CuSO4(s) + HNO3(aq) -> Cu(NO3)2(aq) + H2SO4 (aq)
CuSO4 can be dissolved in water. (refer to the solubility table)
because both products produced are in aqueous form (sulphuric acid and copper (II) nitrate), therefore no observable change.
b) CH3COOH(aq) +NaCl(s) -> CH3COONa(aq) + HCl(aq)
NaCl can be dissolved in water. (refer to the solubility table)
same explanation as in part a.
2014-03-19 12:03:59 補充:
umm... actually it is not no observable change (sorry for the mistakes typed above) coz you will be able to see the solid powder dissolved in both cases. There are reactions in both cases.
Hope u will understand!
2014-03-19 12:09:44 補充:
and no observable change not necessarily equal to no reaction.
No observable change means you cannot observe any changes, for example all the product in the equation are aqueous solution. For no reaction, you can refer back to the displacement reaction part for more information. ur chem book must
2014-03-19 12:10:06 補充:
have some examples that no reaction take places.