Find the integral
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Indefinite integral
2014-03-16 11:08 pm
回答 (2)
2014-03-16 11:44 pm
✔ 最佳答案
∫ ydy / (y²+1)Let u = y²+1
du/dy = 2y
du = 2ydy ydy = (1/2)du
∫ ydy / (y²+1) = (1/2)∫ du/u
=(1/2)ln(u) + C
= (1/2)ln(y²+1) + C
2014-03-17 12:16 am
Mr. Kowk的回答較好
收錄日期: 2021-04-27 20:36:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20140316000051KK00526