Arctan (tan 7π/4):
Select one:
a. -π/4
b. 5π/4
c. 7π/4
d. 3π/4
e. None of these
please give the steps to the solution, thanks
Arctan (tan 7π/4)?
2014-03-11 8:49 pm
回答 (2)
2014-03-11 8:58 pm
Well,
arctan is a bijection from R into (-pi/2 , pi/2)*and
pi is a period of tangent function:
so
as we have : tan(7pi/4) = tan(pi - pi/4) = - tan(pi/4)
we finally get :
arctan(tan(7pi/4)) = artan(tan(- pi/4)) = - pi/4
answer a.
hope it' ll help !!
arctan is a bijection from R into (-pi/2 , pi/2)*and
pi is a period of tangent function:
so
as we have : tan(7pi/4) = tan(pi - pi/4) = - tan(pi/4)
we finally get :
arctan(tan(7pi/4)) = artan(tan(- pi/4)) = - pi/4
answer a.
hope it' ll help !!
2014-03-11 8:51 pm
arctan (tan (7π/4)) = - π/4
[arctan ranges from [- π/2, π/2] ]
Σ
[arctan ranges from [- π/2, π/2] ]
Σ
收錄日期: 2021-05-01 15:05:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20140311124946AA9tPD3