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http://hk.knowledge.yahoo.com/question/question?qid=7013110300269
Question 3
(a)
Note that [(2n-1)+1]/2 = n is the number of rods from the first longest to the shortest.
Consider an arithmetic sequence with first term being 160 and common difference -4.
T(n) = 32
160 + (n-1)(-4) = 32
160 - 4n + 4 = 32
4n = 132
n = 33
(b)
From the first rod of 160 cm to the 33th rod of 32 cm, the total length is
(160+32)*33/2 = 3168 cm
For the bottom part, there are 2*33-1-33 = 32 rods, starting from 36 cm to 160 cm, the total length is
(36+160)*32/2 = 3136 cm
Therefore, the total length is 6304 cm.