急 ! F5 sequence #315

2014-03-09 11:21 pm
請詳細步驟教我計下題 :


圖片參考:https://s.yimg.com/rk/HA05788109/o/1021309802.jpg

回答 (1)

2014-03-09 11:46 pm
✔ 最佳答案
Sol
a100=2i+4i^2+6i^3+…+(200)i^100
=2i+4i^2+6i^3+8i^4+10i^5+12i^6+14i^7+16i^16+…+
194i^97+196i^98+198i^99+200i^100
=(2i+4i^2+6i^3+8i^4)+(10i^5+12i^6+14i^7+16i^16)+…+
(194i^97+196i^98+198i^99+200i^100)
=(2i-4-6i+8)+(10i-12-14i+16)+…+(194i-196-198i+200)
=(4-4i)+(4-4i)+…+(4-4i)
b1=2,d=10-2=8,bm=194
bm=b1+(m-1)*8
194=2+(m-1)*8
m-1=24
m=25
So
a100=25*(4-4i)=100-100i




收錄日期: 2021-04-13 20:18:37
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20140309000051KK00082

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