Find the general solution of linear d.e
xy'-3y=(e^x)(x^4)
Ordinary Differential Equation
2014-02-28 2:59 am
回答 (1)
2014-02-28 4:59 am
✔ 最佳答案
x(dy/dx)-3y=(e^x)(x^4)(x^-3)(dy/dx)+(-3x^-4)y=e^x
(x^-3)(dy/dx)+(dx^-3 /dx)y=e^x
d[x^-3 y]/dx=e^x
x^-3 y=e^x+C
y=(x^3)(e^x)+Cx^3
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