數學二次函數

(1) 甲拋物線: (y-2)=k*(x-3)^2通過A=(5,4) => (4-2)=k(5-3)^2 => k=1/2乙拋物線頂點: x=(3,2)-(4,-3)=(-1,-1)=> 乙拋物線: (y+1)=(-1/2)*(x+1)^2=> y(x)=-(x^2+2x+3)/2.....ans
(2) 對稱軸: x=1 => b=-1標準型: y(x)=a(x-1)^2+c通過: (-1,0),(0,-4)y(-1)=4a+c=0y(0)=a+c=-4相減: a=4/3 => c=-16/3a+b+c=4/3-1-16/3=-15/3=-5.....ans
(3) 對稱軸: x=5 => h=5標準型: y(x)=a(x-5)^2+k通過: (1,2),(0,-7)y(1)=16a+k=2y(0)=25a+k=-7相減: a=-1 => k=18=> y(x)=-(x-5)^2+18=-x^2+10x-7.....ans
(4)A=(-1,6), C=(3,6), D=(-2,11), F=(4,11), B=(2,3)=> 近似拋物線E(0,-3)離開拋物線太遠.....ans

到下面的網址看看吧

▶▶http://misshare168.pixnet.net/blog/post/86950298

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