Find the particular solution of the d.e.
y'=cos2x
which satisfies the condition that y = 2 when x = 0.
Ordinary Differential Equation
2014-02-21 7:34 pm
回答 (1)
2014-02-21 10:35 pm
✔ 最佳答案
y'=cos2xdy/dx = cos2x
∫dy = ∫cos2xdx
y = (1/2)∫cos2xd(2x)
y = (1/2)sin2x + C
y(0) = 2
==> C = 2
y = (1/2)sin2x + 2
收錄日期: 2021-04-27 20:35:00
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