F.4 Math joint variation
2014-02-20 7:56 pm
Y varies jointly as x3 and √z where z ＞ 0, y= 96 when x = 2 and z = 16.(a) Express y in terms of xand z. Let y = ,where is a non-zeroconstant. When x = 2 and z = 16, y =96.(b) Find the value of z when x = 3 and y = 162.
回答 (1)
2014-02-20 9:07 pm
✔ 最佳答案
(a)Let y = kx³√z, where k is a non-zero constant.
When x = 2 and z = 16, y = 96 :
96 = k(2)³√16
32k = 96
k = 3
Hence, y = 3x³√z
(b)
When x = 3 and y = 162 :
(162) = 3(3)³√z
81√z = 162
√z = 2
z = 4
參考: fooks
收錄日期: 2021-04-20 14:53:18
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