莫爾溶解度

2014-02-17 7:18 am
數種碘化合物Ksp如下

TLI Ksp=6.5x10^(-8)

AgI Ksp=8.3x10^(-17)

PbI Ksp=6.4x10^(-9)

BiLI3 Ksp=8.1x10^(-19)


在0.010M 的陽離子溶質(solution of solute cation)中
排列上述化合物的莫爾溶解度大小?
更新1:

PbI2 BiI3 才對

更新2:

3q~~~~~~~~~~~~

回答 (3)

2014-02-18 4:22 pm
✔ 最佳答案
  若在0.010M的陽離子溶質(solution of solute cation)中,其上述各物質的莫耳溶解度大小如下:
  TlI  Ksp = 6.5x10^-8 = 0.01 x [I-]  [I-] = 6.5x10^-6 M
       TlI溶解度= [I-] = 6.5x10^-6 M
  AgI  Ksp = 8.3x10^-17 = 0.01 x [I-]  [I-] = 8.3x10^-15 M
       AgI溶解度= [I-] = 8.3x10^-15 M
  PbI2 Ksp = 6.4x10^-9 = 0.01 x [I-]^2  [I-] = 8.0x10^-4 M
       PbI2溶解度= [I-]/2 = 4x10^-4 M
  BiI3  Ksp = 8.1x10^-19 = 0.01 x [I-]^3  [I-] = 4.3x10^-6 M
       BiI3溶解度= [I-]/3 = 1.4x10^-6 M
  故其溶解度大小排列如下:PbI2>TlI>BiI3>AgI。
2014-03-06 7:01 am
到下面的網址看看吧

▶▶http://misshare168.pixnet.net/blog/post/86950298
2014-02-17 9:14 pm
Lead(II) iodidePbI₂

BiI₃


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