the inclined plane.And a vertical stop on the plane provides a horizontal force
N1 to the sphere. It keeps it at rest.With equations,prove that :
N2^2=N1^2+mg^2
更新1:
其實可不可以用equation去證明N2^2=N1^2+(mg)^2?
F.4 Phy mechanics
2014-02-06 5:47 am
A sphere of mass m is on an inclined plane.All surfaces are smooth.There are total 3 forces acting on the sphere, including its weight mg, normal force N2 provided by
the inclined plane.And a vertical stop on the plane provides a horizontal force
N1 to the sphere. It keeps it at rest.With equations,prove that :
N2^2=N1^2+mg^2
the inclined plane.And a vertical stop on the plane provides a horizontal force
N1 to the sphere. It keeps it at rest.With equations,prove that :
N2^2=N1^2+mg^2
回答 (2)
2014-02-08 8:14 am
✔ 最佳答案
May I offer an alternative solution:Resolve the normal force N2 into vertical and horizontal components. The vertical component = (N2)cos(a), and horizontal component = (N2).sin(a), where a is the angle of slope.
Thus, in equilibrium both horizontally and vertically, we have
Horizontally: N1 = (N2).sin(a)
Vertically: mg = (N2).cos(a)
By squaring both equations and then adding them together,
(N1)^2 + (mg)^2 = (N2)^2[(sin(a))^2 + (cos(a))^2]
i.e. (N1)^2 + (mg)^2 = (N2)^2 since sin(a))^2 + (cos(a))^2 = 1
2014-02-06 6:36 am
有人問過而我又答了一次。
請參考 :
http://hk.knowledge.yahoo.com/question/question?qid=7014012200199
2014-02-06 18:18:07 補充：
其實可不可以用equation去證明N2^2=N1^2+(mg)^2?
唔明你的意思。
對於力學，要用向量，一定要加入方向去計算。
請參考 :
http://hk.knowledge.yahoo.com/question/question?qid=7014012200199
2014-02-06 18:18:07 補充：
其實可不可以用equation去證明N2^2=N1^2+(mg)^2?
唔明你的意思。
對於力學，要用向量，一定要加入方向去計算。
收錄日期: 2021-04-21 16:16:05
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20140205000051KK00238