✔ 最佳答案
1) -2(5-3x)-[3(x-1)-5]= -10+6x-(3x-3-5) = -10+6x-3x+3+5 = 3x-22) Let x and y be the numbers of fries andcokes were sold respectively.Accordingly, we have,y=3x+25____________(1)7x+6y=2400_________(2)Sub. (1) into (2), 7x+6(3x+25)=2400 x=90Sub. x=90 into (1),y=3(90)+25 =295Hence, he sold 90 fries and 295 cokes respectively. 3) Accordingly, we have,b=800a/(800+200)b=4a/5 (simplified) 4) Let x be the answer of the bracket.6+3/2-6x/3=23/6 -6x/3=-11/3 6x=11 x=11/6 5)Let x be the number of failed students,and the number of whole class is 3x.3x/2+3+3+x=3x 3x/2-2x=-6-x=-12 x=12Hence, the number of failed students is 12. 6) x=-0.07(given), then sub. it into theexpression 24x-(5-19x),we have,24(-0.07)- [5-19(-0.07]= -1.68-6.33 = -8.01 7) Let x kg be the weight of A, and weightof C is (x-8)kg, the weight of B is (x+x-8)/2.The sum of their weights=x+(x-8)+[(x+x-8)/2] kg =2x-8+(2x-8)/2kg =(3x-12)kg (it’s an algebraexpression) 8) 45[ (6x-3)-2]-1=87 45(6x-5)=88 6x-5=88/45 6x=313/45 x=313/270 9)(i) 3(x-4)-5(2x-1)=7 3x-12-10x+5 =7 -7x=14 x=-2 (ii) 12-3[x-(1/4x+5)] =1/6x-89 12-3(x-x/4-5)=x/6-89 12-3x+3x/4+15=x/6-89 -3x+3x/4-x/6=-89-12-15 -29x/12=-116 x=48 10) Let x be the number of the cans.Accordingly, we have, 13x+3=16(x-3) x=17Hence, there are 17 cans. And there are candies=13*17+3=224 /=16(17-3)=224 11) Let x km be the distance between places A and B. Accordingly, we have,x/(10+2)+x/(10-2)=5 Solve: x=24Hence, the distance between places A and B is 24 km. 12) The time required will decrease 25%. 13) After burning 3 hours, one was left 1/4, another one was left3/6.Hence, after burning 3 hours, one of the candles is twice as anotherone. 14) The time required=800m/(200m/min-120m/min)=10 mins