1. Hence, or otherwise, find the values of a and b in the following pair of simultan-eous equations.
2a+5b=47ab
4b=3a+10ab
4x=3y
2.(a) Solve
2x-y=4
4(h+ k)=3(h-k)
(b) Using the result in (a), solve
2(h+k)-(h-k)=4
3. There were 6 more male teachers than female teachers in a school. On a rainy day each one of them had brought an umbrella to school. After school the rain st-opped. Only half of the female teachers and 3/4 of the male teachers took their u-mbrellas home. If on that day 12 umbrellas remained and no teacher was absent, what was the total number of teachers in the school?
4. Bonnie's age was 7/8 that of her husband Clyde's when they got married. Bon-
nie gave birth to their daughter Dionne one year after their wedding. When Dion-
ne is 19, i.e. 16 years later from now, the sum of the couple's ages will be 100. H-ow old are Bonnie and Clyde now?
NEED STEP,PLZ!!!
F.2 Maths Problems
2014-01-27 7:02 am
回答 (5)
2014-01-28 10:46 am
✔ 最佳答案
Tai Man :批卷貓 十分好人，已經把第 1 題 化成
{2y + 5x = 47
{4x = 3y + 10
其中 x = (1/a) ; y = (1/b)
簡單了很多，試試去做啦！
但 :
4x=3y
2.(a) Solve
2x-y=4
4(h+ k)=3(h-k)
(b) Using the result in (a), solve
2(h+k)-(h-k)=4
根本睇唔明，點幫你呢？
2014-01-28 02:46:41 補充：
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4. Let the age of Bonnie be B and her husband be C when they got married. B = (7/8)C
1 year later, she gave birth to Dionne, When Dionnie is 19, Bonnie's age will be B + 20 and her husband will be C+ 20. It is stated in the question that (B+20) + (C+20) = 100
B = (7/8)C ...... (1)
(B+20) + (C+20) = 100
B + C = 60
(7/8)C + C = 60
7C + 8C = 480
15C = 480
C = 32
B = (7/8)(32) = 28
Dionne is 3 years old NOW !
Bonnie is 31 and Clyde is 35 NOW!
2014-01-28 19:22:24 補充：
Sorry ! Something wrong.
Dionne is 3 years old NOW !
Bonnie is 32 and Clyde is 36 NOW!
2014-01-31 11:54 pm
2a) Solve, 4x=3y______(1)
2x-y=4______(2)
From (1), we have, x=3y/4______(3)
Sub. (3) into (2),
2(3y/4)-y=4
6y-4y=16
y=8
Sub. y=8 into (3),
x=3(8)/4
=6
2014-01-31 15:55:37 補充：
2b) By using the result of (a), solve,
4(h+k)=3(h-k) ______(1)
2(h+k)-(h-k)=4______(2)
Let x=h+k and y=h-k, then we have,
4x=3y______(3)
2x-y=4______(4)
From (a), we have x=6 and y=8, i.e.
h+k=8________(5)
h-k=6________(6)
Solve: h=7 and k=1.
2x-y=4______(2)
From (1), we have, x=3y/4______(3)
Sub. (3) into (2),
2(3y/4)-y=4
6y-4y=16
y=8
Sub. y=8 into (3),
x=3(8)/4
=6
2014-01-31 15:55:37 補充：
2b) By using the result of (a), solve,
4(h+k)=3(h-k) ______(1)
2(h+k)-(h-k)=4______(2)
Let x=h+k and y=h-k, then we have,
4x=3y______(3)
2x-y=4______(4)
From (a), we have x=6 and y=8, i.e.
h+k=8________(5)
h-k=6________(6)
Solve: h=7 and k=1.
2014-01-28 1:44 am
sorry , 次序倒轉
2.(a) Solve
4x=3y
2x-y=4
(b) Using the result in (a), solve
4(h+k)=3(h-k)
2(h+k)-(h-k)=4
That's the question.
2.(a) Solve
4x=3y
2x-y=4
(b) Using the result in (a), solve
4(h+k)=3(h-k)
2(h+k)-(h-k)=4
That's the question.
2014-01-27 6:09 pm
4x=3y
2.(a) Solve
2x-y=4
4(h+k)=3(h-k)
(b) Using the result in (a), solve
2(h+k)-(h-k)=4
明顯地次序倒轉了，應該是：
2.(a) Solve
4x=3y
2x-y=4
(b) Using the result in (a), solve
4(h+k)=3(h-k)
2(h+k)-(h-k)=4
2.(a) Solve
2x-y=4
4(h+k)=3(h-k)
(b) Using the result in (a), solve
2(h+k)-(h-k)=4
明顯地次序倒轉了，應該是：
2.(a) Solve
4x=3y
2x-y=4
(b) Using the result in (a), solve
4(h+k)=3(h-k)
2(h+k)-(h-k)=4
2014-01-27 7:13 am
{2a + 5b = 47ab
{4b = 3a + 10ab
{2/b + 5/a = 47
{4/a = 3/b + 10
{2y + 5x = 47
{4x = 3y + 10
{4b = 3a + 10ab
{2/b + 5/a = 47
{4/a = 3/b + 10
{2y + 5x = 47
{4x = 3y + 10
收錄日期: 2021-04-27 20:41:47
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