F.4 3條 PHY 考試用 15分

2014-01-12 12:02 am
1. http://i.na.cx/din9G.jpg
momentum唔係0咩?

2. http://i.na.cx/Zv0Rc.jpg
點解ke or pe against displacement 在free falling既情況下係直線既?
ke or pe against time係曲架喎

3. http://i.na.cx/hH8BP.jpg
點解係直線既?

唔該曬,都係溫書唔識既問題

回答 (2)

2014-01-12 2:45 am
✔ 最佳答案
1. As velocity is a vector, so if upward is mv , downward will be -mv.

for momentum. So, the change of it is mv-(-mv)=2mv

2. As v=ds/dt, and if integrate both sides, Ind (v2 /2)=s/t.

Also, KE of a free falling is 1/2 mv2, combine with Ind (v2 /2)=s/t,

KE has a linear relationship with s (displacement)

3. As total energy = KE + PE,

KE = total energy - PE , whatever the total energy,

KE has a linear relationship with -PE in this case.

Also as the object is moved upward, PE will increases, and

by the above, KE will decrease as PE and KE are inverse of

each other
參考: 自己
2014-01-12 2:45 am
Can't open your given links.


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