更新1:
108x⁵ = 6.08X10⁻²⁹ 這裡怎麼解??請問
化學~莫耳溶解度
回答 (1)
2014-01-11 7:31 am
✔ 最佳答案
Ksp(Co₃(AsO₄)₂)=6.80X10⁻²⁹Co₃(AsO₄)₂ <==> 3Co²⁺ + 2AsO₄³⁻
Let the solubility be x mole Co₃(AsO₄)₂ per liter
[Co²⁺] = 3x
[AsO₄³⁻] = 2x
(3x)³(2x)² = 6.08X10⁻²⁹
108x⁵ = 6.08X10⁻²⁹
x = 8.91X10⁻⁷ M
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20140110000016KK04343