等級不足!不能貼圖~
有解答!
更新1:
你好像回答錯題目了~ 這題是有log的題目!
很急!!送上10點!要考試了高一數學對數運算?
2014-01-02 11:28 pm
https://www.facebook.com/photo.php?fbid=1433917013505875&set=a.1433915093506067.1073741831.100006627693181&type=1&theater
等級不足!不能貼圖~
有解答!
等級不足!不能貼圖~
有解答!
回答 (3)
2014-01-03 3:27 am
✔ 最佳答案
log=log<3>=以3為底基本對數公式:log(x*y)=log(x)+log(y)log(x^n)=n*log(x)w=log(18)-log(4)+log(6)=log(2*3^2)-log(2^2)+log(2*3)=log(2)+2*log(3)-2*log(2)+log(2)+log(3)=3*log(3)=3*1.....log<3>(3)=1=3.....ans
2014-01-03 1:42 am
a^x=√2+1，則a^(－x)=?
Sol
a^(－x)
=1/a^x
=1/(√2+1)=(√2－1)/[(√2－1)*(√2+1)]
=(√2－1)/(2－1)
=√2－1
Sol
a^(－x)
=1/a^x
=1/(√2+1)=(√2－1)/[(√2－1)*(√2+1)]
=(√2－1)/(2－1)
=√2－1
2014-01-02 11:55 pm
logx+logy=logxy
logx-logy=logx/y
logx-logy=logx/y
收錄日期: 2021-04-30 18:20:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20140102000010KK02589