It is given that tanx=√2 , find the value of (sinx+2cosx)/(cosx-sinx) and leave your answer in surd form.
NEED STEP,PLZ!!!
Maths Problem
2013-12-26 8:45 pm
回答 (3)
2013-12-26 8:59 pm
✔ 最佳答案
(sinx+2cosx)/(cosx-sinx)divid numerator and Denominator by cosx
= [(sinx+2cosx)/cosx]/[(cosx-sinx)/cosx]
= (sinx/cosx+2cosx/cox)/(cosx/cosx-sinx/cosx)
= (tanx + 2)/(tanx -1)
= ( √2 + 2 )/(√2 - 1)
2013-12-26 14:40:54 補充：
THANK YOU ~~~~~~~~~~~~
2013-12-26 10:04 pm
批卷貓 真的是批開卷，哈哈。
你的學生一定非常多。
你的學生一定非常多。
2013-12-26 9:44 pm
(√2 + 2 )/(√2 - 1)
= (√2 + 2 )/(√2 - 1) * [(√2 + 1)/(√2 + 1)]
= (√2 + 2 )(√2 + 1)/(2-1)
= (√2 + 2 )(√2 + 1)
= 2 + √2 + 2√2 + 2
= 4 + 3√2
= (√2 + 2 )/(√2 - 1) * [(√2 + 1)/(√2 + 1)]
= (√2 + 2 )(√2 + 1)/(2-1)
= (√2 + 2 )(√2 + 1)
= 2 + √2 + 2√2 + 2
= 4 + 3√2
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