(x-a)的平方-4(x-y)(y-a) 求因式分解
=( )( )?
謝謝
(x-a)的平方-4(x-y)(y-a) 求因式分解
2013-12-13 6:34 am
回答 (4)
2013-12-13 2:47 pm
✔ 最佳答案
因式分解(x－a)^2-4(x－y)(y－a)
Sol
(x－a)^2－4(x－y)(y－a)
=(x－a)^2－4(x－y)[(y－a)+(x－y)－(x－y)]
=(x－a)^2－4(x－y)[(y－a)+(x－y)]+4(x－y)^2
=(x－a)^2－4(x－y)(x－a)+4(x－y)^2
=[(x－a)－2(x－y)]^2
=(x－a－2x+2y)^2
=(x－2y+a)^2
2013-12-14 12:13 am
(x-a)^2-4(x-y)(y-a)
=x^2-2ax+a^2-4xy+4ax+4*y^2-4ay
=(x^2-4xy+4*y^2)+2ax-4ay+a^2
=(x-2y)^2+2a*(x-2y)+a^2
=((x-2y)+a)^2
=x^2-2ax+a^2-4xy+4ax+4*y^2-4ay
=(x^2-4xy+4*y^2)+2ax-4ay+a^2
=(x-2y)^2+2a*(x-2y)+a^2
=((x-2y)+a)^2
2013-12-13 8:13 am
換變數, x-y = A, y-a = B
2013-12-13 6:42 am
16用結合律求出來的=(x-x)(y-y)(a-a)餘-4的2次=16
收錄日期: 2021-04-30 18:19:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20131212000010KK05403