20points chemistry(1)

把網上的MO diagram 抄下來加工.


圖片參考：http://imgcld.yimg.com/8/n/HA00075708/o/20131217154019.jpg

Red half-arrow stands for the extra electron in the negatively-charged ion.

a.
Bond order
= [no. of electron pair in Bonding molecular orbital (BMO)] - [no. of electron pair in Anti-bonding molecular orbital (ABMO)]
= 3 - 2 = 1

b.
no unpaired electrons --> diamagnetic

c.
you can see it's pi* , so anti-bonding

d.
obvious

e.
closer to O, so should be O-type

f.
doesn't seems to be likely to accept electrons (and put them into even higher-energy sigma* ABMO.

g.
not sure, but i'll say it's O due to it's higher energy AO. or make up a reason (lol

h.
pls use VSEPR theory to predict.

i.
OF(+), OF, OF(-)
look at the bond order of these 3 species.