When 5.4g of limestone is heated strongly,2.2g of carbon dioxide is given out.Calcuate the percentage purity of calcium carbonate in the sample.(C=12;O=16;Ca=40)
please list out the steps,thx
chemical calculation
2013-12-07 11:37 pm
回答 (1)
2013-12-08 8:33 am
✔ 最佳答案
CaCO3 → CaO + CO2No. of moles of CO2 formed = 2.2 / (12 + 16x2) = 0.05 mol
No. of moles of CaCO3 = 0.05 mol
Mass of CaCO3 = 0.05 x (40 + 12 + 16x3) = 5.0 g
Percentage purity of CaCO3 = (5.0/5.4) x 100% = 92.6%
參考: Adam
收錄日期: 2021-04-16 16:17:49
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