配方法x^2+4x-64=0
過程?
告急!!幫我國二數學配方法?
2013-11-27 1:49 am
回答 (1)
2013-11-27 2:04 am
✔ 最佳答案
x² + 4x - 64 = 0x² + 4x = 64
x² + 4x + (4/2)² = 64 + (4/2)²
(x)² + 2(x)(2) + (2)² = 68
(x + 2)² = 68
x + 2 = √68 或 x + 2 = -√68
x + 2 = 2√17 或 x + 2 = -2√17
x = -2 + 2√17 或 x = -2 - 2√17
參考: andrew
收錄日期: 2021-04-13 19:49:46
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20131126000016KK02882