A transverse traveling wave is described by y=5 sin(2pi(x/10-t/0.05)). x and y are in unit of meters, and t is in unit of seconds.
If the initial phase at some point is 0.6pi , find the position x of this point.
Transverse wave problem
2013-11-25 1:37 am
回答 (1)
2013-11-25 2:38 am
✔ 最佳答案
At t = 0, the wave equation is,y = 2.sin(2.pi.x/10)
If at point x, the phase angle is 0.6pi
thus 0.6pi = 2.pi.x/10
i.e. x = (0.6)(10)/2 m = 3 m
收錄日期: 2021-04-21 22:40:03
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20131124000051KK00152