Matrix

2013-11-22 9:44 pm
Discuss the solutions of
a 1 1 1
1 a 1 a
1 1 a a^2

回答 (2)

2013-11-23 3:56 am
✔ 最佳答案
Please read:


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2013-11-22 22:31:43 補充:
Yes, that is transpose.

The solution in your setting should be in a column vector form.

Instead of writing
[ x ]
[ y ]
[ z ]

we write [ x, y, z ]^T to save space and for clarity.

2013-11-22 22:42:23 補充:
First of all, when I consider performing Gaussian elimination, I can see that I need to divide by a, so my first thought is to separate cases a = 0 and a ≠ 0.

Then, when I tried to do the case for a ≠ 0, I found that I need to divide by a - 1, so I further separate a = 1 and a ≠ 0, 1.

2013-11-22 22:44:37 補充:
For the case of a ≠ 0, 1, I further found that a + 2 exists in the denominator, or I can also say in one step, when a = -2 the system would be inconsistent. Therefore, I finally set one more case for a = -2 and the remained case is for a ≠ 0, 1, -2.

That is why there are in total 4 cases.
2013-11-23 6:28 am
Can you tell me the meaning of T next to each solution? It looks like transpose...
Thanks!!

2013-11-22 22:37:34 補充:
How can you set those cases?
Thanks!!

2013-11-22 22:48:27 補充:
I see , I should perform Gaussian elimination on draft paper first...

2013-11-22 22:48:47 補充:
Your answer is the best.


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