化學題！求解答！

NO(g) + CO₂(g) <===> NO₂(g) + CO(g)

intial
no. of mole of NO = 4
no. of mole of CO₂ = 0.9
no. of mole of NO₂ = 0
no. of mole of CO = 0

At eqm.
no. of mole of NO = 4 - 0.1 = 3.9
no. of mole of CO₂ = 0.9 - 0.1 = 0.8
no. of mole of NO₂ = 0.1
no. of mole of CO = 0.1

At. eqm.

[ NO ] = 3.9/2 = 1.95 mol / dm³
[ CO₂ ] = 0.8/2 = 0.4 mol / dm³
[ NO₂ ] = 0.1/2 = 0.05 mol / dm³
[ CO ] = 0.1/2 = 0.05 mol / dm³

Kc = [ NO₂ ][ CO ] / [ NO ][ CO₂ ] = (0.05)(0.05)/(0.95)(0.4)
= 0.0066

2013-11-21 02:07:34 補充：
解錯了題目意思，題目寫為 [ 有0.1mol co2 剩餘 ] 可能好一點。

At eqm.
no. of mole of CO₂ = 0.1
no. of mole of NO = 4 - 0.8 = 3.2
no. of mole of NO₂ = 0.8
no. of mole of CO = 0.8

2013-11-21 02:09:54 補充：
At. eqm.

[ NO ] = 3.2/2 = 1.6 mol / dm³
[ CO₂ ] = 0.1/2 = 0.05 mol / dm³
[ NO₂ ] = 0.8/2 = 0.4 mol / dm³
[ CO ] = 0.8/2 = 0.4 mol / dm³

Kc = [ NO₂ ][ CO ] / [ NO ][ CO₂ ] = (0.4)(0.4)/(1.6)(0.05)
= 2

答案係2.00！！！！

2013-11-21 11:22:14 補充：
Thx a lot！