數學計算過程不會~超急

2013-11-19 7:22 am
我要計算過程
洩洩~

1. (-9又8分之5)+12分之7- (-24分之11) = -8又12分之7

2. -4分之3 - 【28分之5 - (8分之3+7分之3)】= -8分之1

3. 3又7分之2 -【(2又4分之1-1又7分之3) - (1又6分之5 -3又7分之5)】= 12分之7

4. 【(-3又24分之7)+(-11又18分之7)】+【3又18分之7+(-5又24分之17)】= -17

5. 【(-3分之1) - 5分之1】-【(-2又5分之4) - (-3又6分之5)】= -1又30分之17

6. -3分之1+( -3)的2次方分之3+(-3)的3次方分之9+(-3)的4次方分之27+(-3)的5次方分之81 = -3分之1

回答 (2)

2013-11-19 8:19 am
✔ 最佳答案
1.
(-9又5/8) + (7/12) - (-11/24)
= -(77/8) + (7/12) + (11/24)
= -(231/24) + (14/24) + (11/24)
= (-231 + 14 + 11)/24
= -206/24
= -103/12
= -8又7/12


====
2.
(-3/4) - {(5/28) - [(3/8) + (3/7)]}
= -(3/4) - [(5/28) - (3/8) - (3/7)]
= -(3/4) - (5/28) + (3/8) + (3/7)
= -(42/56) - (10/56) + (21/56) + (24/56)
= (-42 - 10 + 21 + 24)/56
= -7/56
= -1/8


====
3.
(3又2/7) - {[(2又1/4) - (1又3/7)] - [(1又5/6) - (3又5/7)]}
= (3又2/7) - [(2又1/4) - (1又3/7) - (1又5/6) + (3又5/7)]
= (3又2/7) - (2又1/4) + (1又3/7) + (1又5/6) - (3又5/7)
= (23/7) - (9/4) + (10/7) + (11/6) - (26/7)
= (276/84) - (189/84) + (120/84) + (154/84) - (312/84)
= (276 - 189 + 120 + 154 - 312)/84
= 49/84
= 7/12


====
4.
[(-3又7/24) + (-11又7/18)] + [(3又7/18) + (-5又17/24)]
= -(-3又7/24) - (11又7/18) + (3又7/18) - (5又17/24)
= -(79/24) - (205/18) + (61/18) - (137/24)
= -(237/72) - (820/72) + (244/72) - (411/72)
= (-237 - 820 + 244 - 411)/72
= -1224/72
= -17


====
5.
[(-1/3) - (1/5)] - [(-2又4/5) - (-3又5/6)]
= -(1/3) - (1/5) + (2又4/5) - (3又5/6)
= -(1/3) - (1/5) + (14/5) - (23/6)
= -(10/30) - (6/30) + (84/30) - (115/30)
= (-10 - 6 + 84 - 115)/30
= -47/30
= -1又17/30


====
6.
(-1/3) + [3/( -3)²] + [9/(-3)³] + [27/(-3)⁴] + [81/(-3)⁵]
= -(1/3) + (3/9) - (9/27) + (27/81) - (81/243)
= -(1/3) + (1/3) - (1/3) + (1/3) - (1/3)
= -(1/3) + [(1/3) - (1/3) + (1/3) - (1/3)]
= -1/3

2013-11-19 01:24:12 補充:
在發問時已扣除點數,刪除問題只會損人不利己。
參考: micatkie, micatkie
2013-11-22 6:45 am
請注意題號!!!

請注意題號!!!請注意題號!!!

圖片參考:http://imgcld.yimg.com/8/n/AA00628910/o/20131121224329.jpg


收錄日期: 2021-04-13 19:49:18
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20131118000010KK04938

檢視 Wayback Machine 備份