det(A+I)
2013-11-17 7:09 am
Let matrix A=(a(i,j)), i,j=1~n, a(i,j)=cos[(i+j)t], where t= 2π/n.Find det(A+I).
回答 (3)
2013-11-28 5:34 am
✔ 最佳答案
﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣圖片參考：http://imgcld.yimg.com/8/n/HA05107138/o/20131127213327.jpg
2013-11-28 6:41 pm
From A^2, we can get the eigenvalue of A, need not to find the eigenvalue of A^2.
2013-11-17 7:49 am
I tried n = 1, 2, 3, 4, those become 2, 3, -5/4, -4?
I can just notice that sum of all row (or column) gives the same number because of the periodicity of cosine.
No way out from me.
http://i.imgur.com/etQHx4I.png
I can just notice that sum of all row (or column) gives the same number because of the periodicity of cosine.
No way out from me.
http://i.imgur.com/etQHx4I.png
收錄日期: 2021-04-24 10:07:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20131116000051KK00274