中4數一元二次方程:
1)(k-6)2+16=25
2)(3c-4)^2-6=10
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解埋比我=//=
(中4數)(k-6)^2+16=25
2013-11-12 6:03 am
回答 (2)
2013-11-12 6:19 am
✔ 最佳答案
1)(k - 6)² + 16 = 25(k - 6)² + 16 - 25 = 0
(k - 6)² - 3² = 0
(k - 6 - 3) (k - 6 + 3) = 0
(k - 9) (k - 3) = 0
k - 9 = 0 或 k - 3 = 0
k = 9 或 k = 3。
2)(3c - 4)² - 6 = 10
(3c - 4)² - 16 = 0
(3c - 4 - 4) (3c - 4 + 4) = 0
(3c - 8) 3c = 0
3c - 8 = 0 或 3c = 0
c = 8/3 或 c = 0。
2013-11-12 6:50 am
始終都係排第三.........
收錄日期: 2021-04-13 19:48:55
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20131111000051KK00236