數學方程(5題)

2013-11-07 5:38 am
1.-7(3-2k)=9
2.5(2b-6)=4b
3.5w+6-7w-2=-6+3w
4.2[(1-4a)-2(3a+2)]=14
5.-4(3+b)-b=3

請列步驟!!!

回答 (1)

2013-11-07 5:48 am
✔ 最佳答案
1.
-7(3 - 2k) = 9
-21 + 14k = 9
14k = 30
k = 30/14
k = 15/7

2.
5(2b - 6) = 4b
10b - 30 = 4b
10b = 4b + 30
6b = 30
b = 5

3.
5w + 6 - 7w - 2 = - 6 + 3w
-2w + 4 = - 6 + 3w
-5w = -10
w = 2

4.
2[(1 - 4a) - 2(3a + 2)] = 14
2[1 - 4a - (6a + 4)] = 14
2[1 - 4a - 6a - 4] = 14
2[-10a - 3] = 14
-20a - 6 = 14
-20a = 20
a = -1

5.
- 4(3 + b) - b = 3
-12 - 4b - b = 3
-12 - 5b = 3
-5b = 15
b = -3


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