Solve the following exponential equations
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F2 Math
2013-11-05 6:37 am
回答 (4)
2013-11-05 6:46 am
✔ 最佳答案
2^(x+2) + (3)(2^x) = 56(2^2)(2^x) + (3)(2^x) = 56
4(2^x) + (3)(2^x) = 56
(7)(2^x) = 56
(2^x) = 8
x=3
2013-11-06 12:45 am
2^(x).2^(2)+3.2^(x)=56
7.2^(x)=56
2^(x)=8
2^(x)=2^(3)
X=3
7.2^(x)=56
2^(x)=8
2^(x)=2^(3)
X=3
2013-11-05 6:48 am
Here is the solution
2^x(2^2+3) = 56
2^x=56/7
2^x=8
2^x=2^3
x=3
2^x(2^2+3) = 56
2^x=56/7
2^x=8
2^x=2^3
x=3
參考: myself
2013-11-05 6:46 am
2^x (2^2 + 3) = 56
2^x (7) = 56
2^x = 8
x = 3
2^x (7) = 56
2^x = 8
x = 3
收錄日期: 2021-04-13 19:47:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20131104000051KK00227