F2 Math

2013-11-05 6:37 am
Solve the following exponential equations


圖片參考:http://imgcld.yimg.com/8/n/HA00008918/o/20131104223636.jpg

回答 (4)

2013-11-05 6:46 am
✔ 最佳答案
2^(x+2) + (3)(2^x) = 56

(2^2)(2^x) + (3)(2^x) = 56

4(2^x) + (3)(2^x) = 56

(7)(2^x) = 56

(2^x) = 8

x=3
2013-11-06 12:45 am
2^(x).2^(2)+3.2^(x)=56
7.2^(x)=56
2^(x)=8
2^(x)=2^(3)
X=3
2013-11-05 6:48 am
Here is the solution

2^x(2^2+3) = 56
2^x=56/7
2^x=8
2^x=2^3
x=3
參考: myself
2013-11-05 6:46 am
2^x (2^2 + 3) = 56
2^x (7) = 56
2^x = 8
x = 3


收錄日期: 2021-04-13 19:47:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20131104000051KK00227

檢視 Wayback Machine 備份