Maths ( Very urgent !!!!!!!!!)

-(4 - n)
= (-1) x (4 - n) ...... -a = (-1) x a, where a = (4 - n)
= (-1) x 4 - (-1) x n ...... a(b - c) = ab - ac,where a = (-1), b = 4, c = n
= -4 - (-n) ...... (-1) x 4 = -4 and (-1)x n = (-n)
= -4 + (-1) x (-n) ...... -a = +(-1) x a,where a = (-n)
= -4 + n ...... (-1) x (-n) = n

-(4 - n) = -4 + n
Hence 1 - (4 - n) = 1 - 4 + n

兩位，很久不見了～

讓我贊助一下～

數學上負負得正的方程式 (4-n)是表示運算先做，然後1才減(…)的結果方程式理論運算便會把-(減)的算法配入( 內 )的運算1 - (4) 和 - (-n)1 – 4 + 負負得正的+n 不信這理論算法可代入一個數測試n = 3(4-3)=(1)1-(1)=0 按理論結合的程式，順由左至右計1-4+(3) = -3+3 = 0