nuclei of 238PU , 240PU, 241PU

Mass of 1 mole of ²³⁸Pu = 238 g

no. of mole of 1kg ²³⁸Pu = 1000/238 = 4.20168067

no. of nuclei = (4.20168067)(6.02214129 ×1023)

= 2.5303X10²⁴

no. of nuclei of ²⁴⁰Pu = (1000/240)(6.02214129 ×1023)

no. of nuclei of ²⁴¹Pu = (1000/241)(6.02214129 ×1023)

no. of nuclei of ²⁴²Pu = (1000/242)(6.02214129 ×1023)

2013-10-29 00:10:31 補充：
Masterijk , 多謝你的贈點。

2013-10-29 02:08:10 補充：
(6.02214129 ×1023)

is Avogadro constant

it should be (6.02214129 ×10²³)