Please help that New Trend Mathematics P.4.21-Q15 answer! and a formula!!
Thankyou
Help me for my work please
2013-10-29 2:54 am
回答 (2)
2013-10-29 4:01 am
✔ 最佳答案
Let David has $x, Carl has $(x+9), and Hilbert has (x+9)/3.x+(x+9)+(x+9)/3=61
2x+(x+9)/3=52
6x+x+9=156
7x=147
x=21
Thus, David has $21
Carl has $(21+9), ie, $30
Hilbert has (21+9)/3, ie. $10
2013-10-28 20:13:32 補充：
其實設2個未知數、3個未知數都得；
不過設得愈少未知數，就愈簡單，也計得愈快。
2013-10-29 3:02 am
Please upload your question here!! thank
收錄日期: 2021-04-13 19:46:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20131028000051KK00181