F.4 Maths
2013-10-24 9:37 pm
Consider f(x)= (x+1)(x-2) and g(x)=6-2x. Find the values of x such that f(x-1)= g(x)
回答 (2)
2013-10-24 10:10 pm
✔ 最佳答案
Consider f(x)=(x+1)(x－2) and g(x)=6－2x，Find the values of x such thatf(x－1)=g(x)
Sol
f(x－1)=x(x－3)
x(x－3)=6－2x
x^2－3x=6－2x
x^2－x－6=0
(x－3)(x+2)=0
x=3or x=－2
2013-10-27 10:29 pm
f(x-1)= g(x)
[(x+1)-1] [(x-2)-1] = 6-2x
(x+1-1)(x-2+1) = 6-2x
x(x-3)= 6-2x
x^2-x-6 =0
x=3 or -2
[(x+1)-1] [(x-2)-1] = 6-2x
(x+1-1)(x-2+1) = 6-2x
x(x-3)= 6-2x
x^2-x-6 =0
x=3 or -2
參考: me
收錄日期: 2021-04-13 19:46:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20131024000051KK00072