express the function as a taylor series (express your answer in sigma notation)
f(x) = sin(x^3) when x>0
engeering maths taylor series?
2013-10-21 2:58 am
回答 (1)
2013-10-21 3:17 am
✔ 最佳答案
Use the result sin t = Σ(n = 0 to ∞) (-1)^n t^(2n+1)/(2n+1)!.
Let t = x^3:
sin(x^3) = Σ(n = 0 to ∞) (-1)^n (x^3)^(2n+1)/(2n+1)!
............= Σ(n = 0 to ∞) (-1)^n x^(6n+3)/(2n+1)!.
I hope this helps!
收錄日期: 2021-04-11 20:02:54
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