Chemical equilibrium question

2013-10-21 2:04 am
2.5 mole of NOCl(g) were placed in a 1.50dm3 closed container kept at a constant
temperature.After equilibrium was established,it was found that the degree of
dissociation of NOCl(g) is 28%.Calculate Kc.
2NOCl(g) to form 2NO(g) + Cl2(g) it is a reversible reractions.
更新1:

1.5dm3唔洗理?

更新2:

sorry,我睇錯左

更新3:

可以直接將2.5*0.28嗎?

更新4:

即系2.5-(2.5*0.8) 2.5*0.8得出0.7=1.8 再由mole ratio 2:2:1 得到2NO+Cl2既0.7:0.35mole 到計落去,o唔ok?

回答 (1)

2013-10-21 2:36 am
✔ 最佳答案
Please see below !!!

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2013-10-20 21:16:07 補充:
{ 可以直接將2.5*0.28嗎? }?

唔知你想問乜?

2013-10-20 23:11:03 補充:
當 initial conc. = a
degree of dissociation = α

reactant conc. at eqm. = a(1-α)

product conc. at eqm. = aα

當然要再加上 stochiometry coefficient 的修正。例如 [Cl₂] = (1/2)aα

這是很常用和很好用的解題方法。

不過,各師各法,沒有什麽是最好的,正確才是最重要,如果你有什麽方法計到 [ NOCl ] = 1.8 mole/dm³ ,其實都是可以的。

2013-10-20 23:14:57 補充:
即系2.5-(2.5*0.8)
2.5*0.28得出0.7
2.5 - 0.7=1.8
再由mole ratio 2:2:1
得到2NO+Cl2既0.7:0.35mole
到計落去,o唔ok?

卒之睇明白你想說些什麽了,這是 OK 的。

但其實 2.5-(2.5*0.8) 即是 a(1-α)


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